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Math
relations between the 5 shapes
which
form
the
Tangram
puzzle
by G. A. Sarcone & M. J. Waeber
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The
math relations between the 5 basic shapes of the Tangram puzzle
shown below will allow you to create and/or solve new interesting
geometric puzzles. The small isosceles triangle B, the
square C and the rhomboid D of the Tangram all
have the same area, but their surfaces are
different. Actually, the square C has the smallest perimeter
(4a < 2(a+b)).
The large isosceles triangle E is 4 times the size of
the small isosceles triangle A, but curiously its perimeter
is only 2 times as big!
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©1992-2007, Sarcone & Waeber, Genoa |
A
small difference...
The
geometrical shapes in fig. a) and b) seem to be identical...
It's obvious that they are made with the same 4 Tangram pieces,
but thanks to the table above, we can calculate the perimeter
of each geometric figure and find that the perimeter of second
diagram is approx. 1.03 times larger than the first one.
The math expression is:
Pb / Pa =
2(4a+b)/2(a+3b)
By
substituting the value "b" with "a 2",
we obtain: 1.0327...
©1992-2007,
Sarcone & Waeber, Genoa
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Can
you form a perfect trapezium as shown in fig. c below using
all 7 tan pieces? The table above will be helpfull to determine
wether the puzzle is possible or not...
Source: Almanacco
del Matematico, G. Sarcone, 2001
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The
13th shape...
Here
below, you'll find 12 convex polygons you can form with the
Tangram puzzle. There is a 13th convex polygon, which is it?
We mail you the solution if you send us a postcard from your
country! (our address: Archimedes' Lab, Marie-Jo Waeber, CP1700,
16121 Genova Centro, Italy)
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